How would you work out the coordinates of the points?
The diagram shows the curve with equation y = cos (x - 2π/3), -2π < x < 2π. Write down the coordinates of the points at which the curve meets the coordinate axes.
Hi there
Solve it exactly how you would, of course -2pi < x < 2pi is the same as -360 < x < 360
The coordinate axes intersection is when x = 0 and when y = 0
so the easiets to find out is the y intercept
y = cos (x - 2pi/3)
plug in x = o
y = cos ( 0 - 2pi/3)
put your calculator in radians mode(menu -> 2 -> 2) then literally write cos (-2pi/3) and thats the y value
then for x axes intersection plug y = 0
0 = cos ( x - 2pi/3)
to get x, to cos inverse of 0
cos ( x - 2pi/3) = 0
x - 2pi/3 = cos^-1(0) = -270, -90, 90 and 270
But of course, turn that into radians instead of degrees
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so x - 2pi/3 = -270 degrees
which means x - 2pi/3 = -3pi/2
so x = -3pi/2 + 2pi/3 = -5pi/6
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x - 2pi/3 = -90 degrees
which means x - 2pi/3 = -pi/2
so x = -pi/2 + 2pi/3 = -pi/6
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same for positive 90 degrees and 270 degrees solutions
Thank you