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A2 Mechanics: Unit 6 Applications of Kinematics


Shantae P
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Legend A2 Maths, A2 Chemistry, A2 Biology, LSC Queensbury
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Please help with this question 

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Zeeshan Ahmed
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part (a) is quite straight forward, its just asking for the vertical and horizontal components of the velocity. Horizontal being 1cosθ and vertical being 1sinθ

part (b) you need to end up with s = the expression they want. Horizontally, you only have the equation displacement = velocity x time to work with, velocity being '1cosθ'. So we need to get an expression for 'time' to plug in - which we'll get from a suvat vertically.

So you make a SUVAT equation for the vertical motion (s = 0, etc) and try to make t the subject. (Use s = ut + 1/2at^2 then factorise and solve). Now plug that into the s = vt equation and it should eventually turn into the expression required.

Part (c) becomes easy once you've done part (b) - will just be to differentiate and solve

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