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Abdurrahman
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I just want to double check my method

In this question 5 as you can see from my working I have found an expression for “a” now in order to find a I just want to double check that there are two ways to find a: I could now take everything to the power of 3 or I could binomially expand right? 

D62F3A66 71DB 4370 A375 FEA98F690ED5
7157EE8D 49EF 4DF5 8660 25A9A13529E4

 

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Zeeshan Ahmed
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@abdurrahman

Binomially expanding it would be fine, equalling it to = 0, then solving.

However, cube rooting both sides has no problems either - so expanding it would be a bit pointless (in this question)

You might think that you will lose solutions - however you only lose solutions if you divide by something important. Square rooting and cube rooting doesn't lose any solutions.

 

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Abdurrahman
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@zeeshan Jazakallahkhair sir! 

 

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Abdurrahman
Posts: 284
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C0A8B529 F8FA 4E12 A4C3 133E668D00B1

How would u show that the left hand side can be arranged to the rhs (in exact form), I’m stuck in the bit after substituting the limits in and simplifying it so it is in exact form 

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