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Apr 09, 2020 7:51 pm
29 Replies
Apr 09, 2020 7:52 pm
- Why can't I do that
Apr 09, 2020 7:52 pm
-
why do I have to do this instead
Apr 09, 2020 7:53 pm
Here is the question
Apr 10, 2020 4:50 am
I think you've been doing to much maths...!
I can't speak too much though.. Being up at 4:40am and helping with maths xd
cancelling out like terms in fractions is a concept you have to be familiar with from gcse
If you have a/b = b/d
The only way to solve it is by bringing the denominators to the top
You can't just simply cancel them out. I think you're getting confused with this scenario
If the numerators were both the same, then you can cancel them. (since you can "divide both sides by a")
or if the denominators were both the same, you could "times both sides by a" and they would cancel out
Apr 10, 2020 7:54 am
That didn't really answer the question tho,
Cos there the numerator on the RHS and the denominator on the LHS are the same so why does me cancelling them out give me a wrong answer
Apr 10, 2020 7:55 am
Apr 12, 2020 9:52 pm
Someone help with part B please
Apr 12, 2020 9:54 pm
Apr 13, 2020 8:30 am
for the first question
pretend you had this instead (very similar)
they say OX = 3a +1/2b, but we’ve going to work out what it is for ourselves. We do this by going via OM + MX, where MX I called xa because I didn’t know how much of a it is.
so we just worked out what OX is ourselves, but they got that 3a + 1/2b. That means my 1/2b + xa is the same thing as 3a +1/2b - as they are both OX.
So we compare them and realise x must be -3... this means the original question is very easy as we now know how long MX is
Apr 13, 2020 8:39 am
For the second question, it’s a bit more difficult but same concept of finding two things the same then equalling them to each other (equalling the a’s and b’s)
this is what they give, and we should go through the question bit by bit. Work out AB and MN, then MP is just a multiple of MN as it’s on the same line so I call that multiple x
Although it’s a multiple of MN, I can still work out what it actually is via MO +OA + AP
Then after some simplifying I end up with this
so now we’ve got 2 expressions for MP, and just like before what did we do when we have two expressions? We equalled the A’s then equalled the b’s (doesn’t matter if one of the routes looks messy and has letters)
Now the light purple should be equal to the light purple bit and the dark purple should be equal to the dark purple bit
After you equal them, you will have two equations with two unknowns which you now just do simultaneous equations with
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